Exercise - Chapter 3: Logic Gates & Boolean Algebra - Nguyễn Quang Huy

3.1
• Draw the output waveform for the 
A input is shorted to ground (A = 0) 
A input is shorted to the +5 V (A = 1) 
If the output waveform from an OR gate is the
same as the waveform at one of its inputs, the
other input is being held permanently LOW
• If the output waveform from an OR gate is
always HIGH, one of its inputs is being held
permanently HIGH 

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  1. dce 2011 Exercise – Chapter 3 Logic Gates & Boolean Algebra BK TP.HCM Nguyễn Quang Huy huynguyen@cse.hcmut.edu.vn
  2. dce 2011 3.2 + 3.3 • A input is shorted to ground (A=0) • A input is shorted to the +5 V (A = 1)
  3. dce 2011 3.5 • How many different sets of input conditions will produce a HIGH output from a five-input OR gate?
  4. dce 2011 3.8 • Draw the output waveform for the AND gate
  5. dce 2011 3.12 (a) • Boolean expression for output x • Draw the truth table • (A’ + B’)’.B.C
  6. dce 2011 3.16 • Construct the corresponding logic circuit, using AND and OR gates, and INVERTERs y = (M + N)’ + P’Q z = (A + B + C’DE’)’ + B’CD’
  7. dce 2011 3.22 • Complete each expression A+1= D.1= A.A= D+0= B.B’= C+C’= C+C= G+GF= x.0= y+w’y=
  8. dce 2011 3.26 • Simplify each of the following expressions using DeMorgan’s theorems (a) (A’BC’)’ (b) (A(B + C’)’D)’ (c) (A’ + C’ + D’)’ (d) (((AB)’C)’D)’
  9. dce 2011 3.29 • Using only NOR gates, write the output expression
  10. dce 2011 3.32 • Determine conditions will give a warning to the pilot (warning light is ON)
  11. dce 2011 3.35 • Modify the circuit diagram so that it represents more effectively the circuit operation • The input combination that will activate the output
  12. dce 2011 3.41 • Determine the input conditions needed to turn on the LED